The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 4 2⁄15cm . What is the length of either of the remaining equal sides?
Let each of equal sides of an isosceles triangle = x cm.
The base of an isosceles triangle = 4/3 cm
Perimeter of a triangle = 4 2⁄15 cm =. (4*15+2)/15=62/15cm
Sum of three sides = 4 2⁄15 =(4*15+2)/15=62/15cm
Accordding to question :
x + 4/3 + x = (60 + 2)/15
2x = 62/15 - 4/3
2x = (62 - 20)/15
2x = 42/15
x = 42/30
x = 7/5
Each of equal sides of an isosceles triangle = x = 7/5 cm.