Question

The base of an isosceles triangle is $\frac{4}{3}cm$. The perimeter of the triangle is $\frac{62}{15}cm$ What is the length of either of the remaining equal sides?

Answer 1

Given ,

Base of isosceles triangle$=\frac{4}{3}cm$

Perimeter of triangle $=\frac{62}{15}cm$

Let the length of equal sides of the triangle be ‘$s$’.

We know that,

The perimeter of a triangle is sum of all three sides.

So,

$\begin{array}{rcl}& \Rightarrow & \frac{4}{3}+s+s=\frac{62}{15}cm\\ & \Rightarrow & 2s=\frac{62}{15}-\frac{4}{3}\\ & \Rightarrow & 2s=\frac{62-20}{15}\\ & \Rightarrow & 2s=\frac{42}{15}\\ & \Rightarrow & s=\frac{42}{15\times 2}\\ & =& \frac{21}{15}\\ & =& \frac{7}{5}cm\end{array}$

Hence, the length of either of the remaining equal sides are $\frac{7}{5}cm$ each.