Question

The base of an isosceles triangle is 4 cm and its area is 16 $c{m}^2$. If one of the two equal sides of the triangle is k cm, the approximate value of k-1.24 is.....

• A. 9 cm
• B. 7 cm
• C. 10 cm
• D. 8 cm

Answer 1

The correct option is B 7 cm

Area= 16 $c{m}^2$
Area of triangle=1/2*b*h
$16=\frac{1}{2}\ast 4\ast h$
$h=8$
For isosceles triangle,
Using the formula, h=
$h^2=k^2-b^2/4$
$8^2=k^2-4^2/4$
$k^2=68$
$k=8.24$
So, k-1.24=8.24-1.24=7
Answer (B) 7