The base of an isosceles triangle is $5 c m$ . length of each of its equal sides is denoted by $s$ . Express the perimeter of this triangle in terms of $s$ .

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Solution

An isosceles triangle has any two of its sides equal .

Given:Base $= 5$ cm

Other two sides $= s + s = 2 s$

Perimeter of the triangle $= s + s + 5 = 2 s + 5$

$∴$ Perimeter of the triangle $= 2 s + 5$

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The base of an isosceles triangle is 5 cm. length of each of its equal sides is denoted by s . Express the perimeter of this triangle in terms of s.

An isosceles triangle has any two of its sides equal .Given:Base=5cmOther two sides =s+s=2sPerimeter of the triangle=s+s+5=2s+5∴ Perimeter of the triangle =2s+5

The base of an isosceles triangle is $5 c m$ . length of each of its equal sides is denoted by $s$ . Express the perimeter of this triangle in terms of $s$ .

An isosceles triangle has any two of its sides equal .

Given:Base $= 5$ cm

Other two sides $= s + s = 2 s$

Perimeter of the triangle $= s + s + 5 = 2 s + 5$

$∴$ Perimeter of the triangle $= 2 s + 5$