Question

The base of an isosceles triangle is $\frac{4}{3}cm$. The perimeter of the triangle is $4\frac{2}{15}cm$. What is the length of either of the remaining equal sides?

• A. $1\frac{1}{2}cm$
• B. $1\frac{2}{5}cm$
• C. $1\frac{3}{7}cm$
• D. $1\frac{1}{6}cm$

Answer 1

Answer: (B)

$1\frac{2}{5}cm$

$AB=AC$

$x+x+\frac{4}{3}=\frac{62}{15}cm$

$x=\frac{21}{15}=\frac{7}{5}cm=1\frac{2}{5}cm$