Question

The base of an isosceles triangle is $\frac{4}{3}$. The perimeter of the triangle is $4\frac{2}{15}$ cm.

Answer 1

Base$=\frac{4}{3}$cm

Let the equal sides be $x$.

Perimeter$=S_1+S_2+S_3$

$\Rightarrow \frac{62}{15}=x+x+\frac{4}{3}$

$\Rightarrow \frac{62}{15}=2x+\frac{4}{3}$

$\Rightarrow 2x=\frac{62}{15}-\frac{4}{3}$

$\Rightarrow 2x=\frac{62-20}{15}$

$\Rightarrow 2x=\frac{42}{15}$

$\Rightarrow x=\frac{21}{15}$

$\therefore x=\frac{7}{5}$

Thus,two equal sides $=x=\frac{7}{5}$cm