Question

The base of the triangle is $2x+3$ and height is $4x-2$. If it's area is $30\text{sq.m}$. Prepare a quadratic equation from the given information.

Answer 1

Area$=30$

$\frac{1}{2}\times b\times h=30$

$b\times h=60$

$(4x-2)(2x+3)=60$

$8x^2+12x-4x-6=60$

$8x^2+8x-6=60$

$4x^2+4x-33=0$