The base QR of an equilateral triangle PQR lies on the x-axis. The coordinates of the point Q are (4,0) and the origin is the midpoint of the base. Find the co ordinates of points P and R.

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Solution

Here we have
using section formula
coordinates of R=(4,0)
now using distance formula we have PQ=PR
we getP=(0,y)
again we have PQ=QR
using dist formula we get y coordinate as √48
coordinates of P=(0,√48)

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The base QR of an equilateral triangle PQR lies on the x-axis. The coordinates of the point Q are (4,0) and the origin is the midpoint of the base. Find the co ordinates of points P and R.

Here we have using section formula coordinates of R=(4,0) now using distance formula we have PQ=PR we getP=(0,y) again we have PQ=QR using dist formula we get y coordinate as √48 coordinates of P=(0,√48)

Here we have
using section formula
coordinates of R=(4,0)
now using distance formula we have PQ=PR
we getP=(0,y)
again we have PQ=QR
using dist formula we get y coordinate as √48
coordinates of P=(0,√48)