The basic character of $M g O, S r O, K_{2} O$ and $N i O$ increases in the order:

K_{2} O < S r O < M g O < N i O

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N i O < M g O < S r O < K_{2} O

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M g O < N i O < S r O < K_{2} O

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K_{2} O < M g O < N i O < S r O

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Solution

The correct option is C $N i O < M g O < S r O < K_{2} O$
The basic character of oxides decreases along the period towards the right. Thus correct order of basicity is
$K_{2} O > S r O > M g O > N i O$

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Similar questions

The basic character of MgO, SrO, $K_{2} O$ and NiO increases in the order:

M g O, S r O, K_{2} O, N i O and C s_{2} O

The basic character of oxides MgO, SrO, K2O, NiO, Cs2O increase in the order

M g O, S r O, K_{2} O, N i O

C s_{2} O

M g O, S r O, K_{2} O, N i O, C s_{2} O

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