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Nitrogen

The basic cha...

Question

The basic character of the hydrides of $V^{t h}$ group elements decreases in the order :

N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

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S b H_{3} > A s H_{3} > P H_{3} > N H_{3}

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N H_{3} > S b H_{3} > P H_{3} > A s H_{3}

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S b H_{3} > P H_{3} > A s H_{3} > N H_{3}

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Solution

The correct option is B $N H_{3} > P H_{3} > A s H_{3} > S b H_{3}$
All the hydrides of group V elements have one lone pair of electrons on their central atom. Therefore, they can act as Lewis bases. The basic character of these hydrides decreases down the group.
so order is:
$N H_{3} > P H_{3} > A s H_{3} > S b H_{3}$ .

Suggest Corrections

Similar questions

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

Out of NH₃, PH₃, AsH₃ and SbH₃ the most basic hydride is:

N H_{3}, P H_{3}, A s H_{3}, S b H_{3}

S i F_{4} < S i C l_{4} < S i B r_{4} < S i I_{4}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

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