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Introduction to d and f Block Elements

The basic cha...

Question

The basic character of the transition metal monoxides follows the
(At. no. of $T i = 22, V = 23, C r = 24, F e = 26$ )

T i O > V O > C r O > F e O

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V O > C r O > T i O > F e O

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C r O > V O > F e O > T i O

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T i O > F e O > V O > C r O

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Solution

The correct option is A $T i O > V O > C r O > F e O$
The basic character of oxide decreases from left to right in a period of Periodic Table. Thus, the correct order is: $T i O > V O > C r O > F e O$ .

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V O_{4}^{3 -}, C r O_{4}^{2 -}, M n O_{4}^{2 -}, F e O_{4}^{2 -}

F e O

2

V O

5.75

{F e}_{2} O_{3}

V O + {F e}_{2} O_{3} \to F e O + V_{2} O_{5}

V_{2} O_{5}

5.75

F e_{2} O_{3}

V O + F e_{2} O_{3} \to F e O + V_{2} O_{5}

= 56

= 51

= 16

V O + F e_{2} O_{3} \to F e O + V_{2} O_{5}

V_{2} O_{5}

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