Question

The basic character of the transition metal monoxides follows the order:
(Atomic nos. Ti = 22, V = 23, Cr = 24, Fe = 26)

• A. VO > CrO > TiO > FeO
• B. CrO > VO > FeO > TiO
• C. TiO > FeO > VO > CrO
• D. TiO > VO > CrO > FeO

Answer 1

The correct option is D TiO > VO > CrO > FeO

As we move across the period, the size of the atom gets reduced because of increasing effective nuclear charge. So, it will be less easy for the elements on the rightmost end of the d-block to show electropositive character because of increasing effective nuclear charge the outer shell e${}^{-}$s will be more tightly bound to the nucleus. So, the basic character decreases as we move across a period because of a decrease in electropositive character. Hence, the order is:

$TiO>VO>CrO>FeO$