The basic character of the transition metal monoxides follows the order :
(Atomis no. $T i = 22, V = 23, C r = 24, F e = 26$ )

T i O > F e O > V O > C r O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

T i O > V O > C r O > F e O

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

V O > C r O > T i O > F e O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C r O > V O > F e O > T i O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $T i O > V O > C r O > F e O$
All these transition elements are present in the same period.

Basic character of oxide decreases from left to right in a period of periodic table. The decrease in basicity is due to the decrease in atomic size, increase in ionization energy and decrease in electropositive or metallic character as we move from left to right across a period.

As we move across a period, electrons are added to the same valence shell and the atomic size decreases due to the contraction of the shell with increase in the number of protons.

Suggest Corrections

Similar questions

V O_{4}^{3 -}, C r O_{4}^{2 -}, M n O_{4}^{2 -}, F e O_{4}^{2 -}

F e O

2

V O

5.75

{F e}_{2} O_{3}

V O + {F e}_{2} O_{3} \to F e O + V_{2} O_{5}

T i = 22, V = 23, C r = 24, F e = 26

V_{2} O_{5}

5.75

F e_{2} O_{3}

V O + F e_{2} O_{3} \to F e O + V_{2} O_{5}

= 56

= 51

= 16

Join BYJU'S Learning Program