The basic character of transition metal monoxides follows the order:

V O > C r O > T i O > F e O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C r O > V O > F e O > T i O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

T i O > F e O > V O > C r O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

T i O > V O > C r O > F e O

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $T i O > V O > C r O > F e O$
All of these monoxides belong to the same period. As we go from the left to the right, the electropositive character decreases. The effective nuclear charge also increases from the left to the right. Thus, the electropositivity is lowered as we move from the left to right across the periodic table. The appropriate order of basicity will be: $T i O > V O > C r O > F e O$

Suggest Corrections

Similar questions

V O_{4}^{3 -}, C r O_{4}^{2 -}, M n O_{4}^{2 -}, F e O_{4}^{2 -}

F e O

2

V O

5.75

{F e}_{2} O_{3}

V O + {F e}_{2} O_{3} \to F e O + V_{2} O_{5}

V O + F e_{2} O_{3} \to F e O + V_{2} O_{5}

V_{2} O_{5}

V O + F e_{2} O_{3} ⟶ F e O + V_{2} O_{5}

V_{2} O_{5}

V O + {F e}_{2} O_{3} \to F e O + V_{2} O_{5}

V_{2} O_{5}

Join BYJU'S Learning Program