The basic structural unit of feldspar, zeolites, mica and asbestos is:

${(S i O_{3})}^{2 -}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$S i O_{3}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

${(S i O_{4})}^{4 -}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
${(S i O_{4})}^{4 -}$

Feldspar - $K A l S i_{3} O_{8} - N a A l S i_{3} O_{8} - C a A l_{2} S i_{2} O_{8}$

Zeolites - $N a_{2} A l_{2} S i_{2} O_{8} \cdot H_{2} O$

Mica - $K A l_{3} S i_{3} O_{10} (O H)_{2}$

Asbestos- $M g_{3} S i_{2} O_{5} {(O H)}_{4}$

These all are silicates having basic unit ${(S i O_{4})}^{4 -}$

Hence, option (c) is correct.

Suggest Corrections

Similar questions

S i - O - S i

S i

A l

S i^{4 +}

Join BYJU'S Learning Program