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The basic TDM...

Question

The basic TDMA frame structure of a GSM cellular system is comprised of 156.25 bits in a time slot, of which 40.25 bits are overhead bits. If the reserved flag bits are ignored, then the percentage frame efficiency of the TDMA system will be_______%.
74.24

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Solution

The correct option is A 74.24
$Frame efficiency = [1 - \frac{Overhead bit}{Total bits}] \times 100 = (1 - \frac{40.25}{156.25}) \times 100 = 74.241$

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