The battery in the diagram is to be charged by the generator $G$ . The generator has a terminal voltage of 120 Volts when the charging current is 10 Amperes. The battery has an emf of 100 Volts and an internal resistance of 1 Ohm. In order to charge the battery at 10 Amperes charging current, the resistance $R$ should be set at :

0.1 Ω

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0.5 Ω

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1.0 Ω

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5.0 Ω

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Solution

The correct option is C $1.0 Ω$
The generator has a terminal voltage of 120 volts when the charging current is 10 amperes. Hence,
E = V + Ir = 120+ 10(1) = 130V
Hence, in circuit
$R = \frac{E - V}{I}$
$R = \frac{130 - 120}{10} = 1 Ω$

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The correct option is C 1.0 ΩThe generator has a terminal voltage of 120 volts when the charging current is 10 amperes. Hence,E = V + Ir = 120+ 10(1) = 130VHence, in circuitR=E−VIR=130−12010=1Ω

The correct option is C $1.0 Ω$
The generator has a terminal voltage of 120 volts when the charging current is 10 amperes. Hence,
E = V + Ir = 120+ 10(1) = 130V
Hence, in circuit
$R = \frac{E - V}{I}$
$R = \frac{130 - 120}{10} = 1 Ω$