The BE-A binding energy per atomic mass for deuteron and an - particle are X 1and X 2 respectively- The energy released in the reaction will be -

The binding energies of nuclei X and Y are E₁ and E₂ respectively. Two atoms of X fuse together to give one atom of Y and some amount of energy,Q is released. Then

The binding energy of deuteron $(_{1}^{2} H)$ is 1.15 MeV per nucleon and an alpha particle $(_{2}^{4} H e)$ has a binding energy of 7.1 MeV per nucleon. Then in the reaction

$_{1}^{2} H +_{1}^{2} H \to_{2}^{4} H e + Q$

the energy Q released is approximately

Q. Heat of hydrogenation of ethene and benzene are

x_{1}

and

x_{2}

. What will be the correct expression for resonance energy of Benzene?

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The BE/A (binding energy per atomic mass) for deuteron and an α particle are X1and X2 respectively. The energy released in the reaction will be :

The correct option is C 4(X2-X1)BEA]21D=X1,BEA]α=X2BE]D=2X1BE]α=4X2221D→42HeEnergy released =BE]product−BE]reactant =4X2−2(2X1) =4(X2−X1)

The BE/A (binding energy per atomic mass) for deuteron and an $α$ particle are X $_{1}$ and X $_{2}$ respectively. The energy released in the reaction will be :