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Question
The beam shown in figure has a design bending value of
The beam shown in figure has a design bending value of
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Solution
The correct option is B 46.8 kNm
ΣMB=0,
RA×5−6×6−36+8×3+30=0
RA=3.6 kN
RB=6−3.6−8=−5.6 kN
BMD:
BM at A=−6 kN−m
BM at left of C=−10.8 kN−m
BM at right of C=−46.8 kN−m
BM at B=−30 kN−m
Hence design BM= 46.8 kN-m
ΣMB=0,
RA×5−6×6−36+8×3+30=0
RA=3.6 kN
RB=6−3.6−8=−5.6 kN
BMD:
BM at A=−6 kN−m
BM at left of C=−10.8 kN−m
BM at right of C=−46.8 kN−m
BM at B=−30 kN−m
Hence design BM= 46.8 kN-m
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