Question

The below data show the weight (in lb) of $28$ students in a class.


We can make bins of interval length $10$.

• A. 3
• B. 10
• C. 5
• D. 4

Answer 1

Answer: (A), (B)

10

Concept:
We divide the range by width of class interval to find the number of bins.

The weights of $28$ students in a class are denoted below:


The range of the weight data= maximum weight - minimum weight= $(78-48)$ lb= $30$ lb.

In order to break the data ($48$ lb to $78$ lb) in bins of equal interval length, we can take interval length of $10$ lb.

On dividing the range by the interval length, we get
$\frac{30\text{lb}}{10\text{lb}}=3$

$\therefore$ We can make $3$ bins of interval length $10$ lb to break the data with maximum and minimum values of $78$ lb and $48$ lb, respectively.

$\underset{–}{\text{Note:}}$ Suppose, if we take the interval of $5$ lb, then $\frac{30\text{lb}}{5\text{lb}}=6$ bins are required to break the given data.