1
Question
The below distribution shows the number of wickets taken by bowlers in one-day cricket match. Find the mean of the wickets.
NUMBER OF WICKETS20−6060−100100−150150−250250−350350−450NUMBER OF BOWLERS75161223
The below distribution shows the number of wickets taken by bowlers in one-day cricket match. Find the mean of the wickets.
NUMBER OF WICKETS20−6060−100100−150150−250250−350350−450NUMBER OF BOWLERS75161223
Open in App
Solution
Using Step deviation method where assumed mean is a=200 and h=20
Number of Number xidi=xi−200ui=(di20)uifiwickets takenof bowlers(fi) 20−60740−160−8−5660−100580−120−6−30100−15016125−75−3.75−60150−25012200000250−3502300100510350−45034002001030TOTAL45 −106
∴∑fiui∑fi = (−10645)
¯x=a+∑fiui∑fi
¯x=200+(20)(−10645)
=152.89
Using Step deviation method where assumed mean is a=200 and h=20
Number of Number xidi=xi−200ui=(di20)uifiwickets takenof bowlers(fi) 20−60740−160−8−5660−100580−120−6−30100−15016125−75−3.75−60150−25012200000250−3502300100510350−45034002001030TOTAL45 −106
∴∑fiui∑fi = (−10645)
¯x=a+∑fiui∑fi
¯x=200+(20)(−10645)
=152.89
Suggest Corrections
48
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
