The below reaction is a type of- 12H- - 11H-01n

The correct option is A γ,n _1^2H+ γ⟶ _1^1H+_0^1n The above reaction is #160;( γ,n ) type reaction. γ = Bombarding particle n = Eject ...

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Standard X

Physics

Nuclear Fission

The below rea...

Question

The below reaction is a type of:

$_{1}^{2} H + γ ⟶_{1}^{1} H +_{0}^{1} n$

γ, n

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α, p

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β, n

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None of these

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Solution

The correct option is A $γ, n$
$_{1}^{2} H + γ ⟶_{1}^{1} H +_{0}^{1} n$

The above reaction is ( $γ, n$ ) type reaction.

$γ =$ Bombarding particle
$n =$ Ejected particle

Hence, option A is correct.

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Similar questions

The below reaction is a type of:

_{3}^{6} L i +_{0}^{1} n ⟶_{2}^{4} H e +_{1}^{3} H

Q. Write the complete nuclear reactions:
(a)

_{4}^{9} B e +_{2}^{4} H e ⟶_{6}^{12} C +

______
(b)

_{1}^{3} H ⟶_{2}^{3} H e +

________
(c)

_{7}^{14} N +_{2}^{4} H e ⟶_{8}^{17} O +

_______
(d)

_{92}^{235} U +_{0}^{1} n ⟶_{38}^{92} S r + X e + 3_{0}^{1} n

(e)

_{3}^{7} L i +_{0}^{1} n ⟶ 2_{2}^{4} H e +

_______
(f)

_{92}^{238} U +

_______

⟶_{92}^{239} U ⟶_{93}^{239} N p +

_______
(g)

_{7}^{14} N +_{0}^{1} n ⟶

________

+_{1}^{3} H

(h)

_{3}^{7} L i +

_______

⟶_{4}^{8} B e + γ

-radiations
(i)

_{1}^{2} H +

______

⟶_{2}^{4} H e +_{0}^{1} n

(j)

_{13}^{27} A l +_{0}^{1} n ⟶_{11}^{24} N a +

_______
(k)

_{13}^{27} A l +_{2}^{4} H e ⟶

________

+_{1}^{1} H

(l)

_{92}^{235} U +_{0}^{1} n ⟶

_______

+_{52}^{137} T e +_{40}^{97} Z r

(m)

_{34}^{86} S e ⟶

_______

+ 2_{- 1}^{0} e

Q. If

α, β, γ

are the roots of the equation

x^{3} - 3 x + 11 = 0

, what is the equation whose roots are

(α + β), (β + γ)

and

(γ + α)

Q. If

sin (2 α - β - γ) + 8 sin (2 β - γ - α) + 27 sin (2 γ - α - β) = P

and

sin (α + β) + sin (β + γ) + sin (γ + α) = Q

then P+Q is equal to

Q. If the roots of the equation

x^{n} - 1 = 0

are

1, α, β, γ, . . .,

show that

(1 - a) (1 - β) (1 - γ) . . . . = n

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The below reaction is a type of:21H+γ⟶11H+10n

The correct option is A γ,n21H+γ⟶11H+10nThe above reaction is (γ,n) type reaction.γ= Bombarding particlen= Ejected particleHence, option A is correct.

The below reaction is a type of:

$_{1}^{2} H + γ ⟶_{1}^{1} H +_{0}^{1} n$

The correct option is A $γ, n$
$_{1}^{2} H + γ ⟶_{1}^{1} H +_{0}^{1} n$

The above reaction is ( $γ, n$ ) type reaction.

$γ =$ Bombarding particle
$n =$ Ejected particle

Hence, option A is correct.