Question

The below table gives goals scored by three football teams in 3 weeks.

$\begin{array}{cccc}Teams\downarrow Weeks\to & Week1& Week2& Week3\\ TeamA& 4& 7& 4\\ TeamB& 2& 0& 10\\ TeamC& 7& 5& 6\end{array}$

The team with the highest average wins. Find the team that is most likely to win.

• A. Team A
• B. Team B
• C. Team C
• D. All of the above.

Answer 1

The correct option is C Team C

Given table:
$\begin{array}{cccc}Teams\downarrow Weeks\to & Week1& Week2& Week3\\ TeamA& 4& 7& 4\\ TeamB& 2& 0& 10\\ TeamC& 7& 5& 6\end{array}$

Using this, we will make one more table that shows the average of each team for 3 weeks.

$\begin{array}{cc}Teams& Average\\ TeamA& \frac{4+7+4}{3}=\frac{15}{3}=5\\ TeamB& \frac{2+0+10}{3}=\frac{12}{3}=4\\ TeamC& \frac{7+5+6}{3}=\frac{18}{3}=6\end{array}$

Since the average goal score of Team C is the highest, the chance of Team C winning is the highest.