The bent-shape of the molecule may develop from which of the following hybridization(s)?

s p^{3} d

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s p^{3}

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s p

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s p^{2}

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Solution

The correct options are
B $s p^{3}$
D $s p^{2}$
A) $s p^{3} d$ molecule develops trigonal bipyramidal.
B) $s p^{3}$ molecule with no lone pair develops tetrahedral, with one lone pair develops pyramidal, with two lone pairs develop bent shape.
C) $s p$ molecule develops linear shape.
D) $s p^{2}$ molecule with one lone pair is bent shaped.
Hence options B & D are correct.

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Question 03

The types of hybrid orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}$ respectively are expected to be

(a) $s p, s p^{3} a n d s p^{2}$

(b) $s p, s p^{2} a n d s p^{3}$

(d) $s p^{2}, s p^{3} a n d s p$

L i H + {B - -}_{2} H_{6} \to 2 L i B - - H_{4}

B e H_{2}

C H_{2} B r_{2}

P F_{6}^{-}

B F_{3}

s p, s p^{2}, s p^{3}

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