Question

The best height to jump safely from a tree is $t$. The height of the tree is given as$43.5=6t+\frac{48}{32}$yd

• A. 7

Answer 1

The correct option is A 7
Given:

$43.5=6t+\frac{48}{32}$

$⟹43.5-\frac{48}{32}=6t$

$⟹43.5-1.5=6t$

$⟹42=6t$

$⟹\frac{42}{6}=t$

$⟹7=t$

$\therefore \text{The safest height to jump is 7 yd}$.