The correct option is C t−Bu−MgBr + Benzyl bromide
t−butylMgBr gives butane as the major product and tertiary Grignard reagent is preferred. The product formed is butane. When Grignard reagent like alkylMgBr reacts with alkene we get alkane corresponding to the alkyl part of Grignard reagent. In this reagent, the C atom is more electronegative than Mg hence the alkyl part acts as a nucleophile and takes an active H to form the corresponding alkane and here butane.