Question

The biaxial stress system in an element is shown in the figure. Which of the following will give the normal stress in $N/m{m}^2$ in plane BD making an angle of 45° with the plane BA?

• A. 25
• B. 20
• C. 15
• D. 10

Answer 1

The correct option is D 10

$\because$ ${\sigma }_n=\frac{{\sigma }_1+{\sigma }_2}{2}+\frac{{\sigma }_1-{\sigma }_2}{2}cos2\theta$

$\because \theta =45{}^{\circ }$

$\therefore {\sigma }_{n45{}^{\circ }}=\frac{60-40}{2}+0=10N/m{m}^2$