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Binding Energy

The binding e...

Question

The binding energies of the nuclei A and B are $E_{a}$ and $E_{b}$ respectively. Three nuclei of the element B fuse to give one nucleus of element 'A' and an energy 'Q' is released. Then $E_{a}, E_{b}, Q - -$ are related

E_{a} - 3 E_{b} = Q

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3 E_{b} - E_{a} = Q

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E_{a} + 3 E_{b} = Q

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E_{b} + 3 E_{a} = Q

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Solution

The correct option is B $3 E_{b} - E_{a} = Q$
The binding energy of reactants is $Q_{r} = 3 E_{b}$
The binding energy of product is $Q_{p} = E_{a}$
the enrgy released will be $Q = Q_{r} - Q_{p} = 3 E_{b} - E_{a}$

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