wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The binding energies of the nuclei of 42He , 73Li , 126C and 147N are 28 , 52 , 90 , 98 Me V respectively. Which of these is most stable?

A
42He
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
73Li
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
126C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
147N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 42He
The nucleus with higher binding energy will be more stable.

We have to calculate the binding energy per nucleus from the given values of binding energies.

The binding energy of a nucleus is calculated by the following formula :

Binding Energy =Binding Energy per NucleusMass Number

Binding energy per nucleus of 42He=284=7

Binding energy per nuclei of 73Li=527=7.42

Binding energy per nuclei of 126C=9012=7.5

Binding energy per nuclei of 147N=9814=7

So, the carbon (126C) nucleus will be more stable because, in carbon, the binding energy per nucleus is maximum (7.5).

Hence, option (C) is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Isotopes and Isotones
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon