Question

The binding energies per nucleon for deuteron .(${}_1^{2}H$) and helium (${}_2^{4}He$) are 1.1 MeV and 7.0 MeV respectively. The energy released, when two deuterons fuse to form a helium nucleus is

• A. 9.2 MeV
• B. 11.3 MeV
• C. 17.5 MeV
• D. 23.6 MeV

Answer 1

The correct option is D 23.6 MeV

Avg $B{E}_D=1.1MeV$

Avg $B{E}_{He}=7MeV$
$B{E}_D=2.2MeV$

$B{E}_{He}=28MeV$
$2_1^{2}H{\to }_2^{4}He$

$\therefore$ Energy released $=28-2\left(2.2\right)$
$=23.6MeV$