Question

The binding energy of an electron in the ground state of an atom is equal to $24.6\mathrm{eV}.$ Find the energy required to remove both the electrons from the atom?

Answer 1

Binding energy:

• Binding energy is known as the amount of energy required to separate a particle from a system of particles or to disassemble a system of particles into individual parts.
• Binding energy is especially applicable to subatomic particles in atomic nuclei, to electrons bound to nuclei in atoms, and to atoms and ions bound together in crystals.

Step 1: Given data:

The binding energy of an electron in the ground state of an atom is given as $=24.6\mathrm{eV}$
We also know that, the binding energy of Helium atom is known to be$=24.6\mathrm{eV}$

Step 2: calculation of energy required to remove both the electrons from the atom:

By the removal of one electron from the Helium atom, it becomes a single electron species, for which the ionization energy can be given as:

$\mathrm{H}{\mathrm{e}}^{+}$atom $=-13.6\times 4=-54.4\mathrm{eV}$
Now, the energy required to remove both electrons present in the $\mathrm{He}$ atom is given as$=-54.4+24.6=79\mathrm{eV}$
$\therefore$Hence, the energy required to remove both the electrons from the atom is $79\mathrm{eV}.$