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Question

The binding energy of the second excited state of Li2+ ion is:

A
13.60 eV
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B
27.20 eV
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C
24.17 eV
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D
18.20 eV
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Solution

The correct option is A 13.60 eV
Since we are calculating the binding energy of the second excited state of Li2+ ion, we need to calculate, E3 to E.
ΔE3 to =EE3
=0(13.63232) eV
=13.6 eV

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