wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The binding energy of the second excited state of Li2+ ion is:

A
13.60 eV
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
27.20 eV
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
C
24.17 eV
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
D
18.20 eV
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
Open in App
Solution

The correct option is A 13.60 eV
Since we are calculating the binding energy of the second excited state of Li2+ ion, we need to calculate, E3 to E.
ΔE3 to =EE3
=0(13.63232) eV
=13.6 eV

flag
Suggest Corrections
thumbs-up
6
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon