The binding energy of the second excited state of Li2+ ion is:
A
13.60eV
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B
27.20 eV
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C
24.17eV
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D
18.20eV
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Solution
The correct option is A13.60eV Since we are calculating the binding energy of the second excited state of Li2+ ion, we need to calculate, E3 to E∞. ΔE3to∞=E∞−E3 =0−(−13.63232)eV =13.6eV