CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Binding Energy

The binding e...

Question

The binding energy per each nucleon in the neighborhood of medium nuclei is $8.5 M e V$ and the binding energy per each nucleon is about $7.6 M e V$ in the neighborhood of Uranium. The energy released in the fission of $U^{236}$ is roughly

A

212 e V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

212 M e V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

2.12 M e V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

0.9 M e V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $212 M e V$
In the fission reaction, Uranium breaks into two medium nucie.
Mass no. is conserved, hence the no.of nucleons remain const. on the product and reactant side

Energy released $=$ Change in Nuclear binding energy

Energy released $= 236 (8.5 - 7.6) = 212.4 M e V$

Suggest Corrections

thumbs-up

1

Similar questions

Q. A heavy nucleus

X

240

and binding energy per nucleon

7.6 M e V

is split into two fragments

Y

Z

of mass numbers

110

130

the binding energy of nucleons in

Y

8.5 M e V

.

Calculate the energy

Q

released per fission in

M e V .

Q. Consider the fission reaction

{_{92} U}^{236} ⟶ X^{117} + Y^{117} + {_{0} n}^{1} + {_{0} n}^{1}

ie., two nuclei of same mass number

117

are formed plus two neutrons. The binding energy per nucleon of

X

Y

8.5 M e V

U^{236}

7.6 M e V

. Find the total energy liberated.

Q. A heavy nucleus

X

240

and binding energy per nucleon

7.6 M e

is split into two fragment

Y

Z

of mass numbers

110

130

. The binding energy per nucleon in

Y

Z

8.5 M e V

per nucleon. Calculate the energy

Q

released per fission in

M e V

Q. Consider a fission reaction

_{92} U^{236} \to X^{117} + Y^{117} +_{0} n^{1} +_{0} n 1

ie., two nuclei of same mass number 117 are formed plus two neutrons. The binding energy per nucleon of X and Y is 8.5MeV where as of

U^{236}

is 7.6MeV. The total energy liberated will be about-

Q. In a fission reaction

_{92}^{236} U \to^{117} X +^{117} Y + n + n

. The binding energy per nucleon of

X

Y

8.5 M e V

^{236} U

7.6 M e V

. The total energy liberated will be about

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Binding Energy

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon