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Byju's Answer

Standard XII

Physics

Binding Energy

The binding e...

Question

The binding energy per nucleon is maximum in the case

_{92}^{235} U

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_{56}^{141} B a

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_{26}^{56} F e

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_{4}^{2} H e

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Solution

The correct option is D $_{26}^{56} F e$
The above binding energy per nucleon curve clearly shows that $_{26}^{56} F e$ has maximum BE per nucleon.
This value of the BE of the element accounts for it being the most stable element.

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Similar questions

Q. Assertion :Nuclear binding energy per nucleon is in the order

_{4}^{9} B e >_{3}^{7} L i >_{2}^{4} H e

. Reason: Binding energy per nucleon increases linearly with difference in number of neutrons and protons.

The binding energy of deuteron $(_{1}^{2} H)$ is 1.15 MeV per nucleon and an alpha particle $(_{2}^{4} H e)$ has a binding energy of 7.1 MeV per nucleon. Then in the reaction

$_{1}^{2} H +_{1}^{2} H \to_{2}^{4} H e + Q$

the energy Q released is approximately

Q. The Binding energy per nucleon of

_{3}^{7} L i

and

_{2}^{4} H e

nucleon are

5.60 M e V

and

7.06 M e V

, respectively. In the nuclear reaction

_{3}^{7} L i +_{1}^{1} H \to_{2}^{4} H e +_{2}^{4} H e + Q

, the value of energy

Q

released is

Q. The binding energy per nucleon of

_{1}^{2} H

and

_{2}^{4} H e

are

1.1 M e V

and

7.0 M e V

respectively. Energy released in the process

_{1}^{2} H +_{1}^{2} H \to_{2}^{4} H e

Q. Binding energy per nucleon is maximum

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The binding energy per nucleon is maximum in the case

The correct option is D 5626FeThe above binding energy per nucleon curve clearly shows that 5626Fe has maximum BE per nucleon.This value of the BE of the element accounts for it being the most stable element.

The correct option is D $_{26}^{56} F e$
The above binding energy per nucleon curve clearly shows that $_{26}^{56} F e$ has maximum BE per nucleon.
This value of the BE of the element accounts for it being the most stable element.