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Binding Energy

The binding e...

Question

The binding energy per nucleon of $_{2} H e^{4}$ is $7.075$ MeV. What is its total binding energy?

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Solution

Binding energy per nucleon $= 7.075 M e V$
No. of nucleon $= 4$
So, Total Binding Energy $= 7.075 \times 4 = 28.3 M e V$

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