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Binding Energy

The binding e...

Question

The binding energy per nucleon of $C^{12}$ is $E_{1}$ and that of $C^{13}$ is $E_{2}$ . The energy required to remove one neutron from $C^{13}$ is

12 E_{1} + 12 E_{2}

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13 E_{2} - 12 E_{1}

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12 E_{2} - 13 E_{1}

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13 E_{2} + 12 E_{1}

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Solution

The correct option is A $13 E_{2} - 12 E_{1}$
Binding energy of $C^{12}$ is
$B E_{1} = 12 \times E_{1}$
Binding energy of $C^{13}$ is
$B E_{2} = 13 \times E_{2}$
Thus, energy required to remove one neutron from $C^{13}$ is
$△ E = B E_{2} - B E_{1} = 13 E_{2} - 12 E_{1}$ .

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