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Question

The binding energy per nucleon of deuteron (1H2) and helium (2He4) are 1.1 MeV and 7.0 MeV, respectively. The energy released when two deuterons fuse to form a helium nucleus is

A
36.2 MeV
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B
23.6 MeV
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C
47.2 MeV
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D
11.8 MeV
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E
9.31 MeV
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Solution

The correct option is B 23.6 MeV
The nuclear reaction is,
1H2+1H22He4+Q
Total binding energy of helium nucleus
=4×7=28 MeV
Total binding energy of each deuteron
=2×1.1=2.2 MeV
Hence, energy released when two deuteron fuse to form helium,
=282×2.2=2844=23.6 MeV.

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