The binding energy per nucleon of iron atom is approximately.

13.6 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8.8 MeV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Infinity

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 MeV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 8.8 MeV
The maximum binding energy per nucleon occurs at around mass number $A = 50$ , and corresponds to the most stable nuclei. Iron nucleus $F^{56}$ is located close to the peak with a binding energy per nucleon value of approximately $8.8 M e V$ . It’s one of the most stable nuclides that exist.

Suggest Corrections

Similar questions

Q. The binding energy of an element is 64 MeV. If the binding energy per nucleon is 6.4 MeV, then the number of nucleons are 10.

Q. The binding energy of Helium nucleus is

28

Mev. What is it's average binding energy per nucleon ?

Q. The binding energy of

_{8} O^{16}

127 M e V

. Its binding energy per nucleon is :

Q. The binding energy per nucleon of

_{2} H e^{4}

7.075

MeV. What is its total binding energy?

The binding energy of deuteron $(_{1}^{2} H)$ is 1.15 MeV per nucleon and an alpha particle $(_{2}^{4} H e)$ has a binding energy of 7.1 MeV per nucleon. Then in the reaction
$_{1}^{2} H +_{1}^{2} H \to_{2}^{4} H e + Q$
the energy Q released is

Join BYJU'S Learning Program