The birthday of Ms. Y was celebrated six days before Ms. X who was born on 4th october 1999. The independence day of that year fell on Sunday. On which day did Ms. Y celebrate her birthday, if it was not a leap year.

Tuesday

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Monday

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Wednesday

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Sunday

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Solution

The correct option is A Tuesday
a) Ms.X birthday = 4th October
and Ms.Y birthday = 28th September
Given, 15 August was on Sunday
Now, calculating odd days
August (16 days left) = 2 odd days and
September (till 28th) = 0 odd day
i.e. 2 odd days
So,Ms.Y was born 2 days after Sunday = Tuesday.

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