Question

The bisector of any two adjacent angles of a square form an isosceles-right-angled triangle.
If the above statement is true then mention answer as 1, else mention 0 if false

Answer 1

Given: ABCD is a square. OA and OB bisect $\angle A$ and $\angle B$
$\angle A=90$ (ABCD is a square)
$\angle OAB={45}^{\circ }$ (OA bisects $\angle A$)
Similarly, $\angle OBA={45}^{\circ }$ (OB bisecs $\angle B$)
Now, In $△OAB$
$\angle OAB=\angle OBA={45}^{\circ }$
Hence, OAB is an Isosceles triangle
Sum of angles = 180
$\angle OAB+\angle OBA+\angle BOA=180$
$45+45+\angle BOA=180$
$\angle BOA={90}^{\circ }$
Thus, $△OBA$ is a right angled Isosceles triangle.