The bisectors of any two adjacent angles of a parallelogram intersect at
A
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B
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C
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D
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Solution
The correct option is C Let ABCD be parallelogram ∠A+∠B=180∘ [Adjacent angles of parallelogram are supplementary] ∠A2+∠B2=180∘2=90∘ [Bisectors divide the angles into half] ∠AOB=180−∠A2+∠B2=90∘