The bisectors of any two adjacent angles of a parallelogram intersect at an angle of
Let ABCD be parallelogram
∠A+∠B=180∘ [Adjacent angles of parallelogram are supplementary]
∠A2+∠B2=180∘2=90∘ [Bisectors divide the angles into half]
∠AOB=180−∠A2+∠B2=90∘