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Exterior Angle of a Triangle = Sum of Opposite Internal Angles

The bisects o...

Question

The bisects of exterior angles at B and C of triangle ABC meet at O.If angle A=x°, then angle BOC will be _____.

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The bisects of exterior angles at B and C of $Δ A B C$ , meet at O. If $∠ A = x^{\circ}$ , then $∠ B O C$ =

Q. The bisects of exterior angle at B and C of ΔABC meet at O. If ∠A = x°, then ∠BOC =

(a)

90 ° + \frac{x °}{2}

90 ° - \frac{x °}{2}

180 ° + \frac{x °}{2}

180 ° - \frac{x °}{2}

Q. In the triangle ABC, the bisectors of the exterior angles B and C meet at O. Given angle

B A C = 60^{\circ}

A B C = 70^{\circ}

. Find angle BOC.

Q. In the triangle ABC, the bisectors of the exterior angles B and C meet at O. Given

∠ B A C = 60^{\circ} a n d ∠ A B C = 70^{\circ}

∠ B O C

.

Q. In the triangle

A B C

, the bisectors of exterior angles

B

C

O

∠ B A C = 70^{\circ}

∠ A C B = 50^{\circ}

∠ B O C

.

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Exterior Angle of a Triangle = Sum of Opposite Internal Angles

Standard IX Mathematics

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