The bit rate for a signal, which has a sampling rate of $8 k H z$ and where $16$ quantisation levels have been used is :

32000 b i t s / s e c

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

16000 b i t s / s e c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

64000 b i t s / s e c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

72000 b i t s / s e c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $32000 b i t s / s e c$
If $n$ is the number of bits per sample, then number of quantisation level $= 2$ ,
Since the number of quantisation level is $16$ -
$\Rightarrow 2^{n} = 16 \Rightarrow n = 4$
$∴$ Bit rate = Sampling rate $\times$ No. of bits per sample $= 8000 \times 4 = 32, 000 b i t s / s e c$ .

Suggest Corrections

Similar questions

x (t) = s i n c (200 t) s i n c^{2} (1000 t)

s a m p l e / s e c .

1 V / m s e c

\frac{3}{32 π} cm / \sec

\frac{3}{16 π} cm / \sec

\frac{3}{48 π} cm / \sec

\frac{1}{24 π} cm / \sec

Join BYJU'S Learning Program