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Question

the block $$AandBarereleasedasshowninthefigure.frictionisabsenteverywhere.FindtheratioofmagnitudeofaccelerationofblockBandaccelerationofblockA$
1092369_16c51957951e492f90f6fddde8609f8b.png

A
3/4
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B
4/3
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C
1
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D
zero
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Solution

The correct option is B 4/3
Let the acceleration of block B be b downwards and acceleration of block A be towards left.

The acceleration acting to normal to the contact surface must be equal and opposite so,
bsin37=acos37
So,
ba=cot37=43

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