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Finding Friction's Magnitude

the block A...

Question

the block $$A $a n d$ B $a r e r e l e a s e d a s s h o w n i n t h e f i g u r e . f r i c t i o n i s a b s e n t e v e r y w h e r e . F i n d t h e r a t i o o f m a g n i t u d e o f a c c e l e r a t i o n o f b l o c k$ B $a n d a c c e l e r a t i o n o f b l o c k$ A$

A

3 / 4

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B

4 / 3

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C

1

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D

z e r o

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Solution

The correct option is B $4 / 3$
Let the acceleration of block B be b downwards and acceleration of block A be towards left.

The acceleration acting to normal to the contact surface must be equal and opposite so,
bsin37=acos37
So,
$\frac{b}{a} = c o t 37 = \frac{4}{3}$

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Similar questions

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Q. A block of mass m is placed on a wedge. The wedge can accelerate in four manners marked as (1), (2), (3) and (4) as shown in the figure. If the normal reactions in situations (1), (2), (3) and (4) are

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Q. A block of mass

m

is placed on a wedge. The wedge can be accelerated in four manners marked as (1), (2), (3) and (4) as shown in the figure. If the normal reactions in the situation (1), (2), (3) and (4) are

N_{1}, N_{2}, N_{3}

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N_{4} > N_{3} > N_{1} > N_{2}

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b_{2} > b_{3} > b_{1} > b_{4}

Which of the above statements are correct?

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