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Question

The block of mass 1 kg slides down a curved track which forms one quadrant of a circle of radius 1 m as shown in the figure. The speed of block at the bottom os the track is v=2 ms1. The work done by the force of friction is:
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A
+4 J
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B
4 J
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C
8 J
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D
+8 J
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Solution

The correct option is C 8 J
Work done by the friction is the change in energy of the block.
Work done by friction=K.EP.E=12mv2mgh
work done=(0.5)(1)(22)(1)(10)(1)=8 J

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