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Standard XII

Physics

The 'e' Equation

The block of ...

Question

The block of mass $m$ is at rest just before the collision,
Find out the total momentum of the blocks just AFTER the collision?

12 k g - m / s

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16 k g - m / s

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18 k g - m / s

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24 k g - m / s

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32 k g - m / s

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Solution

The correct option is E $32 k g - m / s$
Using momentum conservation, total momentum after collision $=$ total momentum before collision $= (4 \times 8) + m (0) = 32 k g - m / s$

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The block of mass m is at rest just before the collision,Find out the total momentum of the blocks just AFTER the collision?

The correct option is E 32kg−m/sUsing momentum conservation, total momentum after collision = total momentum before collision =(4×8)+m(0)=32kg−m/s

The block of mass $m$ is at rest just before the collision,
Find out the total momentum of the blocks just AFTER the collision?

The correct option is E $32 k g - m / s$
Using momentum conservation, total momentum after collision $=$ total momentum before collision $= (4 \times 8) + m (0) = 32 k g - m / s$