Question

The block of mass $M$ moving on the frictionless horizontal surface collides with the spring of spring constant $K$ and compresses it by length $L$. The maximum moment of the block after collision is

• A. $\sqrt{MK}L$
• B. $\frac{K{L}^2}{2M}$
• C. $zero$
• D. $\frac{M{L}^2}{K}$

Answer 1

The correct option is A $\sqrt{MK}L$

Maximum kinetic energy of the spring is given by,

$KE=\frac{1}{2}k{x}^2$

Given, $x=L$

$KE=\frac{1}{2}k{L}^2$

$KE=\frac{P^2}{2m}$

$\frac{P^2}{2m}=\frac{1}{2}k{L}^2$

$\therefore P=L\sqrt{KM}$