Question

The block shown in the figure is in equilibrium. Find acceleration of the block just after the string is cut.

• A.
• B.
• C.
• D. None

Answer 1

The correct option is C

kxcos${53}^{\circ }$ = mg $\Rightarrow$ kx = 5$\frac{mg}{3}$ ...(i)

Just after the string burns; tension in the spring remains same, so no acceleration in vertical direction. Let a is the acceleration in horizontal direction,

then Kx sin ${53}^{\circ }$ = ma ...(ii)

From (i) and (ii) a = $\frac{4g}{3}$