wiz-icon
MyQuestionIcon
MyQuestionIcon
14
You visited us 14 times! Enjoying our articles? Unlock Full Access!
Question

The block shown moves with constant velocity on a horizontal surface. Two of the forces on it are shown. A frictional force exerted by the surface is the only other horizontal force on the block. The frictional force is

246075_846e72f4400241749da1bf88777e65b7.png

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2 N, leftward
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2 N, rightward
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
slightly more than 2 N, leftward
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2 N, leftward
The block moves with constant velocity on horizontal surface, this indicates the acceleration of block is zero,. From newton's IInd law of motion net external force should be zero in case of zero acceleration.
Fnet= 0
Taking right direction as positive force direction
5 N + f N+ (-3) N=0 => f= -2 N where f is frictional force.
the frictional force value is 2N in leftward direction, hence correct answer is B.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon